nfer 11a
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Quick reply, the post Verbal Reasoning session G & T's are kicking in.
Question 50, use the following Lowest Common Multiple methodology.
http://www.elevenplusexams.co.uk/forum/ ... highlight=
Question 43 cannot see the problem. Can only suggest that you complete all numbers to 3 decimal places, i.e 1.1 becomes 1.100 (1 plus 100 thousandths), and work out which number in thousandths is closest to 1.000
Question 50, use the following Lowest Common Multiple methodology.
http://www.elevenplusexams.co.uk/forum/ ... highlight=
Question 43 cannot see the problem. Can only suggest that you complete all numbers to 3 decimal places, i.e 1.1 becomes 1.100 (1 plus 100 thousandths), and work out which number in thousandths is closest to 1.000
Do you mean 43 or 48? If 48, the vertical legs of the zig-zag will = y, and the horizontal legs will = x.dadofkent wrote:Quick reply, the post Verbal Reasoning session G & T's are kicking in.
Question 50, use the following Lowest Common Multiple methodology.
http://www.elevenplusexams.co.uk/forum/ ... highlight=
Question 43 cannot see the problem. Can only suggest that you complete all numbers to 3 decimal places, i.e 1.1 becomes 1.100 (1 plus 100 thousandths), and work out which number in thousandths is closest to 1.000
Therefore 2x + 2y