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 Post subject: HOW TO SOLVE
PostPosted: Sun Dec 24, 2006 9:08 pm 
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Joined: Sun Dec 17, 2006 10:40 am
Posts: 36
6x -7 =3x +5 whats the value of x
i need a method not just guessing numbers.


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 Post subject:
PostPosted: Sun Dec 24, 2006 9:14 pm 
To solve most teachers recommend the following:

First collect all x terms on the side where you have the most

6x -7 =3x +5
6x -7 -3x = 3x + 5 -3x [subtracting 3x from both sides]

so,
3x - 7 = 5

now collect the numbers

3x -7 +7 = 5 + 7 [adding 7 to both sides]
3x = 12
x = 4
Now check in original if you have time


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 Post subject: huh
PostPosted: Sun Dec 24, 2006 9:24 pm 
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Joined: Sun Dec 17, 2006 10:40 am
Posts: 36
in simpiler words


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 Post subject:
PostPosted: Sun Dec 24, 2006 9:34 pm 
Can you do the ones with x terms on one side without guessing?

Eg 7x - 5 = 16

collect numbers

7x - 5 + 5 = 16 + 5 [ we need to add 5 to both sides to undo the '-5']


so 7x = 21

then x = 3

If you can I will try and explain another one


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 Post subject:
PostPosted: Mon Dec 25, 2006 2:00 am 
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Joined: Tue Nov 14, 2006 5:04 pm
Posts: 89
hi,

This bbc site may be useful. I have used it my daughter. She found it helpful. Key stage 3 mathu, under algebra.

http://www.bbc.co.uk/schools/ks3bitesiz ... ndex.shtml


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 Post subject:
PostPosted: Mon Dec 25, 2006 9:25 am 
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Joined: Sun Dec 17, 2006 10:40 am
Posts: 36
thanx alot


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