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 Post subject: More help needed
PostPosted: Fri Jan 07, 2011 6:24 pm 
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Joined: Sun Jan 02, 2011 9:12 pm
Posts: 88
Please help with this one...

A school gate needs the correct combinationof four digits in the correct order

When 5648 is tried 2 digits are wrong
When 3628 is tried 2 digits are wrong
When 3147 is tried 2 digits are wrong
When 5629 is tried 2 digits are wrong
When 1258 is tried all the digits are wrong

What is the correct combination of digits?


Thank you


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 Post subject: Re: More help needed
PostPosted: Fri Jan 07, 2011 7:23 pm 
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Joined: Fri Nov 17, 2006 8:54 pm
Posts: 1770
Location: caversham
JGBallard wrote:
Please help with this one...

A school gate needs the correct combinationof four digits in the correct order

When 5648 is tried 2 digits are wrong
When 3628 is tried 2 digits are wrong
When 3147 is tried 2 digits are wrong
When 5629 is tried 2 digits are wrong
When 1258 is tried all the digits are wrong

What is the correct combination of digits?


Thank you


1258 are all wrong so applying this,
*64* so 64 are correct
36** so 36 are correct
3*47 so 347...
*6*9.....69

Collecting in ORDER, 3,6,4, then 7 or 9? As two had to be wrong in 3*47, 7 is wrong leaves, 3649.

A version of VR codes.

Where did the question come from?


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 Post subject: Re: More help needed
PostPosted: Fri Jan 07, 2011 7:39 pm 
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Joined: Sun Jan 02, 2011 9:12 pm
Posts: 88
Thank you so much! :)


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 Post subject: Re: More help needed
PostPosted: Fri Jan 07, 2011 10:00 pm 
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Joined: Sun Jan 02, 2011 9:12 pm
Posts: 88
sorry, just looking at this again...I can see why the 8 is incorrect in the first line...but I'm lost after that..please help!

Thanks


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 Post subject: Re: More help needed
PostPosted: Fri Jan 07, 2011 10:16 pm 
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Joined: Sat Mar 06, 2010 11:39 pm
Posts: 2080
Take away 1 2 5 8 from all options as all 4 numbers are wrong.

So,

Option A: 5648 leaves you with 6 4 (two nos correct)
Option B: 3628 leaves you with 3 6 (two nos correct)
Option C: 3147 leaves you with 3 4 7 (two nos correct)
Option D: 5629 leaves you with 6 9 (two nos correct)

We know there's a 3 and a 4 in the code because the first two options are correct. That must mean there is no 7 in option C.

That leaves you with: 3 6 4 9 (option B shows you that 3 comes before 6 and option D shows you that 9 comes after 6).


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