This is from a Schofield & Sims
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This is from a Schofield & Sims
Take a one digit integer.
Multiply it by 3. Add 8. Divide by 2. Subtract 6.
Now you have your starting integer.
What is it?
I would do it by solving (3x+8)/2 - 6 = x. But is there a way to do it without using algebra? I think at KS2 level they wouldn't expect that.
Multiply it by 3. Add 8. Divide by 2. Subtract 6.
Now you have your starting integer.
What is it?
I would do it by solving (3x+8)/2 - 6 = x. But is there a way to do it without using algebra? I think at KS2 level they wouldn't expect that.
Re: This is from a Schofield & Sims
Trial and error?Long Journey wrote:Take a one digit integer.
Multiply it by 3. Add 8. Divide by 2. Subtract 6.
Now you have your starting integer.
What is it?
I would do it by solving (3x+8)/2 - 6 = x. But is there a way to do it without using algebra? I think at KS2 level they wouldn't expect that.
1 x 3 = 3, + 8 = 11, /2 = fraction
So try the even numbers?
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Re: This is from a Schofield & Sims
Thank you stevew. I suppose with such a small set of numbers to try trial and error makes sense.