Bond question

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Midas
Posts: 26
Joined: Sat Mar 31, 2012 8:46 pm

Bond question

Post by Midas »

Please help trying to help my son with this and our answer is different to bond's answer.



This is from 9-10 book2. Paper 9 question 21

Wurzitts & daughters make super-wurzitts. Each super-wurzitts is 3m long. On the conveyor belt there is room for 11 super-wurzitts with a space of 1m between each pair of super-wurzitts. How long is the conveyor belt.

Thanks
poppit
Posts: 196
Joined: Tue Nov 23, 2010 3:15 pm
Location: Birmingham

Re: Bond question

Post by poppit »

11 x 3m = 33m gives the total length of the super-wurzitts if they were laid end to end.
If the wording means that there is 1m between each super-wurzitt then there are 10 spaces each 1m long = 10m (11 objects will have a total of 10 spaces between them)
So the total length is 44m.
Midas
Posts: 26
Joined: Sat Mar 31, 2012 8:46 pm

Re: Bond question

Post by Midas »

Thanks for that I got 43m, my son got 44m. Bond have 38m .
faitaccompli
Posts: 357
Joined: Mon Dec 05, 2011 6:44 pm

Re: Bond question

Post by faitaccompli »

the wurlizters are in pairs, so only 5m is needed between 11 of them.
38m in total!
poppit
Posts: 196
Joined: Tue Nov 23, 2010 3:15 pm
Location: Birmingham

Re: Bond question

Post by poppit »

Finger trouble on my part, I meant to type 43m not 44m! :oops:

faitaccompli - totally agree with you, I couldn't decide if a super-wurzitt was already a pair because it had two things in it (a wurzitt and a daughter) - a bit like a pair of socks! Or whether two super-wurzitts together make a pair - I now know it was the latter!
Midas
Posts: 26
Joined: Sat Mar 31, 2012 8:46 pm

Re: Bond question

Post by Midas »

Thank you falta, it was doing my head in.
Midas
Posts: 26
Joined: Sat Mar 31, 2012 8:46 pm

Re: Bond question

Post by Midas »

Oops sorry faita!
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