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 Post subject: Maths book 1 paper 3 question 16Posted: Thu May 17, 2012 12:35 pm

Joined: Tue May 15, 2012 5:03 pm
Posts: 15
How do you work out what is the nearest number to 1000 but smaller than 1000, into which 38 will divide with no remainder?

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 Post subject: Re: Maths book 1 paper 3 question 16Posted: Thu May 17, 2012 12:42 pm

Joined: Mon Feb 22, 2010 2:50 pm
Posts: 533
One way would be to divide 1000 by 38 which would give you 26 remainder 12 and take the 12 away from 1000.

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 Post subject: Re: Maths book 1 paper 3 question 16Posted: Thu May 17, 2012 2:39 pm

Joined: Tue May 15, 2012 5:03 pm
Posts: 15
hi bel the answer is 988 but how do you work it out need explanation?

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 Post subject: Re: Maths book 1 paper 3 question 16Posted: Thu May 17, 2012 2:46 pm

Joined: Tue Oct 04, 2011 8:44 am
Posts: 1390
standard long division I would have thought - my DD calls it the bus shelter method for some reason

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 Post subject: Re: Maths book 1 paper 3 question 16Posted: Thu May 17, 2012 3:25 pm

Joined: Thu May 10, 2012 8:30 am
Posts: 247
standard long division I would have thought - my DD calls it the bus shelter method for some reason

Unlikely that long division is necessary: this is an excellent example of where "chunking" is a far faster method, and I suspect the question is set assuming that's how you'll do it, because it's particularly tidy. 1000/38 is "a bit more than 25" (assuming you recognise that 1000/40 is 25). 25 * 38 is 950 (divide 38 by 4 and multiply the result by 100). Once you know that 25 x 38 = 950, the rest is pretty straightforward. Dividing 1000/38 using standard long division is much harder (100/38 = 2 remainder 24, but it's not obvious, and 240/38 = 6 remainder 12 isn't obvious at all).

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 Post subject: Re: Maths book 1 paper 3 question 16Posted: Thu May 17, 2012 3:34 pm

Joined: Tue Oct 04, 2011 8:44 am
Posts: 1390
Dd would probably chunk - I am way too old for that to come naturally to me

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 Post subject: Re: Maths book 1 paper 3 question 16Posted: Thu May 17, 2012 4:47 pm

Joined: Mon Jun 18, 2007 2:32 pm
Posts: 6962
Location: East Kent
The 'bus stop ' method is short multiplication; took me ages to work out what they were talking about and I was the teacher!

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 Post subject: Re: Maths book 1 paper 3 question 16Posted: Sat Jun 16, 2012 10:29 am

Joined: Sun Sep 05, 2010 9:14 am
Posts: 66
I would do it simply (because I'm not good enough to do it in a complicated way) by timesing by 10 - so 20 x 380=760.

30 x is 1140 so too much. So add 5 x:

760 +190 =950 so you know has to be 26 times at 988.

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 Post subject: Re: Maths book 1 paper 3 question 16Posted: Sat Jun 16, 2012 10:38 am

Joined: Thu May 10, 2012 8:30 am
Posts: 247
tiredmumof2 wrote:
I would do it simply (because I'm not good enough to do it in a complicated way) by timesing by 10 - so 20 x 380=760.

30 x is 1140 so too much. So add 5 x:

760 +190 =950 so you know has to be 26 times at 988.

That's chunking, as it happens.

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 Post subject: Re: Maths book 1 paper 3 question 16Posted: Sun Jan 26, 2014 11:06 pm

Joined: Sun Jan 26, 2014 10:23 pm
Posts: 1
I am new to this forum, and my DD will take her 11+ in 2015. I find this forum very useful with all the great tips. Trying to devise a plan to help her deal with the exam conditions and think logically. I'm surely going to use this forum a lot in the coming days.
Was curious about the question posted by OP, and am just giving my opinion. The dividend is what is required, not the quotient. So chunking is the ideal method.
I would teach my DD to use easy multiples of 38 and get close to 1000
38x10=380
double it
760
38x5=190
50 left
Agree with tiredmumof2 there, not completely The answer is 988. The quotient is irrelevant in this particular context.

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