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PostPosted: Sat Jun 16, 2012 8:47 pm 
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Joined: Thu Sep 29, 2011 10:43 am
Posts: 160
Take a one digit integer.
Multiply it by 3. Add 8. Divide by 2. Subtract 6.
Now you have your starting integer.
What is it?

I would do it by solving (3x+8)/2 - 6 = x. But is there a way to do it without using algebra? I think at KS2 level they wouldn't expect that. :?:


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PostPosted: Sat Jun 16, 2012 9:00 pm 
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Joined: Fri Nov 17, 2006 8:54 pm
Posts: 1770
Location: caversham
Long Journey wrote:
Take a one digit integer.
Multiply it by 3. Add 8. Divide by 2. Subtract 6.
Now you have your starting integer.
What is it?

I would do it by solving (3x+8)/2 - 6 = x. But is there a way to do it without using algebra? I think at KS2 level they wouldn't expect that. :?:


Trial and error?

1 x 3 = 3, + 8 = 11, /2 = fraction

So try the even numbers?


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PostPosted: Sun Jun 17, 2012 9:32 pm 
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Joined: Thu Sep 29, 2011 10:43 am
Posts: 160
Thank you stevew. I suppose with such a small set of numbers to try trial and error makes sense.


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