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 Post subject: Help with 2 questions
PostPosted: Wed Sep 12, 2012 8:07 pm 
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Joined: Wed Sep 12, 2012 7:02 pm
Posts: 24
This is my first post on this forum. I needed help with 2 questions.
[img]F:\Question%201[/img]
[img]F:\Question%202[/img]


I have tried to paste the images.

Thank You


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PostPosted: Wed Sep 12, 2012 8:11 pm 
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Joined: Fri Oct 21, 2011 2:49 pm
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Hi and welcome

Sorry but it hasn't worked.

You could quote papers and q numbers or do a search for
the questions by paper number and q number. They may have been answered already.


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PostPosted: Wed Sep 12, 2012 8:16 pm 
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it's from the Habs 2007 paper Questions 29 & 30. Can't copy & paste as the images are not being copied


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PostPosted: Wed Sep 12, 2012 8:23 pm 
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let me try if this works

file:///F:/Ques%201.jpg

file:///F:/Question%202.jpg


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PostPosted: Wed Sep 12, 2012 8:37 pm 
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Joined: Mon Aug 22, 2011 8:20 pm
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Location: Warwickshire
paper downloadable from here

Q29

Figure 1: 4 Nodes 4 Regions 6 Arcs
Figure 2: 6 Nodes 8 Regions 12 Arcs
Figure 3: 2 Nodes 1 Regions 1 Arcs
Figure 4: 7 Nodes 5 Regions 10 Arcs

Arcs = Nodes + Regions -2

Q30

How many diagonals does a hexagon have? 9
How many diagonals does an octagon have? 20
Complete the following table:


Number of sides = 3 Number of diagonals = 0
Number of sides = 4 Number of diagonals = 2
Number of sides = 5 Number of diagonals = 5
Number of sides = 6 Number of diagonals = 9
Number of sides = 7 Number of diagonals = 14
Number of sides = 8 Number of diagonals = 20
Number of sides = n Number of diagonals = (n-3)x(n/2)
Number of sides = 20 Number of diagonals = 170

from each vertex you can draw diagonals to each of the vertices except itself, and the two adjacent to it (which will form the sides of the polygon) - i.e. n(the number of vertices - which is the same as the number of sides) - 3
multiply this by the number of vertices
then divide by two as you would otherwise be counting each diagonal from both its source end and its destination end
hence (n-3)x(n/2)


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PostPosted: Thu Sep 13, 2012 1:24 pm 
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Joined: Wed Sep 12, 2012 7:02 pm
Posts: 24
Thank You Okanagan. I had worked out most of the answers but the relations were proving a real challenge.

Thank You so much again


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