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PostPosted: Sun Dec 15, 2013 3:13 pm 
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Completely stumped. From the Godolphin and Latymer website:

AB and C represent different digits.

AB + C =50

BC + A = 41

What are the values of A, B and C?


Yikes. This is tricky. Any suggestions how to tackle.


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PostPosted: Sun Dec 15, 2013 3:45 pm 
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A,B and C are digits .... think about that.


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PostPosted: Sun Dec 15, 2013 5:22 pm 
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I have just realised how easy this is. I thought the first two 'digits' were to be multiplied first. Doh!

Thanks anyhow for looking


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PostPosted: Sun Dec 15, 2013 5:36 pm 
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That's why I only gave a hint!


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PostPosted: Mon Dec 16, 2013 11:11 am 
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10A + B + C = 50 :arrow: (1)
10B + C + A = 41 :arrow: (2)

(1) - (2) :arrow: 9A - 9B = 9

:arrow: A = B + 1

So substituting this in (2) gives:

10B + C + B + 1 = 41
11B + C = 40

Since C is a single digit the only value B can have is 3.

Therefore, C = 7

And A = 4.


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PostPosted: Mon Dec 16, 2013 1:56 pm 
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It is simpler than that:
AB + C =50 :arrow: C can't be more than 9 so A must be 4 (and B+C must be 10 although you don't need that fact)

BC + A = 41 :arrow: given A is 4, BC must be 37 so B is 3 and C is 7


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PostPosted: Mon Dec 16, 2013 2:01 pm 
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Okanagan wrote:
It is simpler than that:
AB + C =50 :arrow: C can't be more than 9 so A must be 4 (and B+C must be 10 although you don't need that fact)

BC + A = 41 :arrow: given A is 4, BC must be 37 so B is 3 and C is 7


Yeah, you're right. I over complicated it a bit!


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