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PostPosted: Sat Jan 04, 2014 2:21 pm 
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Question 38 - Can anyone help with this question?


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PostPosted: Sat Jan 04, 2014 2:24 pm 
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Can you type it out?


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PostPosted: Sat Jan 04, 2014 2:33 pm 
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Sorry - it is copied out below.

Magda and her friends go to the cinema.
They buy 1 large tub of popcorn, 4 fizzy drinks and 10 packets of crisps. The bill comes to £10.89.

Lena and her friends go to the cinema.
They buy 1 large tub of popcorn, 3 fizzy drinks and 7 packets of crisps. The bill comes to £8.64.

How much would it cost to buy 1 large tub of popcorn, 1 fizzy drink and 1 packet of crisps?


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PostPosted: Sat Jan 04, 2014 2:51 pm 
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What is the answer?


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PostPosted: Sat Jan 04, 2014 2:53 pm 
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don't know - tried simultaneous equations and ratios but am stumped.

There seems to be some information missing unless I'm missing something really obvious and being tunnel visioned which is why I hope someone will come along and solve the riddle


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PostPosted: Sat Jan 04, 2014 2:59 pm 
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Well this is what I did ...

I subtracted to get what one fizzy drink and 3 packets of crisps is.

Then I rewrote the first as:

1 large tub of popcorn + 1 fizzy drink + 1 packet of crisps + (3 fizzy drinks and 9 packets of crisps) is 10.89

Does that help?


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PostPosted: Sat Jan 04, 2014 3:12 pm 
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Thank You - quite neat although would a 10/11 year old know how to expand an equation.


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PostPosted: Sat Jan 04, 2014 3:22 pm 
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I think it's a bit tricky but it doesn't need algebra.

The key is understanding that you don't need the individual price of each thing.


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PostPosted: Sat Jan 04, 2014 4:52 pm 
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DS has worked it out as follows

1P + 4D + 10C = £10.89
1P + 3D + 7C = £8.64
1D + 3C = £2.25
3D + 9C = £6.75

£10.89 - £6.75 = £4.14

Hope this helps.


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PostPosted: Sat Jan 04, 2014 5:00 pm 
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Future that's what I did without the need for algebra!


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