Letts question
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Letts question
30 people go to a restaurant. All the diners order from the below menu;
Three course meal: £12
Two course meal: £9
If the total bill was £345, how many people ordered a three course meal?
How do I explain the method to DD?
Could anyone please guide me?
Three course meal: £12
Two course meal: £9
If the total bill was £345, how many people ordered a three course meal?
How do I explain the method to DD?
Could anyone please guide me?
Re: Letts question
Think about how the answer can end in a 5 in the units ...
Re: Letts question
345= 12 a + 9b -----1
where a =no of peeps eating 3 course
B = no peeps eating 2 course
30 people eating therefore a+b = 30 ----------2
Simply simultaneous equations now:
A= 30 - b. subst into equation 1
345= 12(30-b) +9b
345 = 360-12b+9b
15=3b
B= 5
From ------2. 30=a+5
a= 25
Therefore 25 peeps ate a 3 course meal and 5 ate a two course meal
where a =no of peeps eating 3 course
B = no peeps eating 2 course
30 people eating therefore a+b = 30 ----------2
Simply simultaneous equations now:
A= 30 - b. subst into equation 1
345= 12(30-b) +9b
345 = 360-12b+9b
15=3b
B= 5
From ------2. 30=a+5
a= 25
Therefore 25 peeps ate a 3 course meal and 5 ate a two course meal
Re: Letts question
DS split 345 into multiples of 9 and 12, and by just looking at number he saw a pattern 300 and 45, and could see 45 is a multiple of 9, (9 x5) and 12 goes into 300 25 times hence, 25 people ordered £12 main course
Re: Letts question
Thanks everyone. dd gets it now. not sure if she will be able to apply this in the exam scenario ..tomorrow.