Maths problem - help needed today!

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herewegoagain
Posts: 104
Joined: Tue Sep 04, 2007 12:10 pm

Maths problem - help needed today!

Post by herewegoagain »

Can anyone help with this question which is baffling us:

The last part of a telephone number has four digits eg:

7814 1487 2103 2772

The last part of the telephone number can start with any digit apart form zero. The other three digits can by any number. How many four digit numbers are there?

Thanks!
Wallasey
Posts: 91
Joined: Mon Dec 31, 2007 2:28 am
Location: Wirral

Post by Wallasey »

Each number has ten possible values, 0-9, and you find the possible number of combinations by multiplying them together. So with 2 numbers it would be 10 x 10 = 100 possibles. Then x another 10 for three numbers = 1000. For the final number, if you can't have zero it's only x 9 this time, so the total would be 9000 possible numbers.
herewegoagain
Posts: 104
Joined: Tue Sep 04, 2007 12:10 pm

Post by herewegoagain »

That's really helpful - thanks.
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