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 Post subject: Susan Daughtrey Pack 1 Test 3 q71Posted: Tue Oct 19, 2010 9:55 pm

Joined: Mon Apr 28, 2008 9:57 am
Posts: 223
Can someone please help with the sum below, dS is demanding a mark for the question as he thinks there are two answers to it.

(15[32]2 ) (14[30]2)
(12[?]4)

Answer is 28 but ds thinks it can also be 26
Is there a technique to working out the correct answer?

Thank you

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 Post subject: Re: Susan Daughtrey Pack 1 Test 3 q71Posted: Tue Oct 19, 2010 10:03 pm

Joined: Wed Jul 07, 2010 11:04 am
Posts: 455
Quote:
(15[32]2 ) (14[30]2)
(12[?]4)

(15x2)+2=32
(14x2)+2=30
(12x2)+4=28
How does your ds get to 26?

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Everyone is a genius, but if you judge a fish by its ability to climb a tree, it will think it is stupid.

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 Post subject: Re: Susan Daughtrey Pack 1 Test 3 q71Posted: Tue Oct 19, 2010 10:22 pm

Joined: Mon Apr 28, 2008 9:57 am
Posts: 223
Hi turtleglos

DS thought he should be adding 2 each time instead of the number on the right.

Many thanks

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 Post subject: Re: Susan Daughtrey Pack 1 Test 3 q71Posted: Wed Oct 20, 2010 12:17 pm

Joined: Wed Sep 23, 2009 12:47 pm
Posts: 698
Location: Essex
Couldn't it also be 52? Product of the two outside numbers plus the number to the right.

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 Post subject: Re: Susan Daughtrey Pack 1 Test 3 q71Posted: Wed Oct 20, 2010 12:35 pm

Joined: Wed Jul 07, 2010 11:04 am
Posts: 455
Quote:
Couldn't it also be 52? Product of the two outside numbers plus the number to the right.
Couldn't it also be 52? Product of the two outside numbers plus the number to the right.

It could, but I would guess that that is not an option in the multiple choice.

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Everyone is a genius, but if you judge a fish by its ability to climb a tree, it will think it is stupid.

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 Post subject: Re: Susan Daughtrey Pack 1 Test 3 q71Posted: Wed Oct 20, 2010 1:50 pm

Joined: Fri Nov 13, 2009 5:39 pm
Posts: 7
Hi Josa. The instructions for this type of question in the SD papers state that "The three numbers in each group are related in the same way". I believe that your son's alternative answer does not use one of the numbers in the group for the final group? I would say his answer is therefore incorrect. It is my understanding that you must include both numbers outside the brackets for these types of questions.

As an aside however, when I first looked this up I used the Tutors papers as an example, and their instructions are "In these questions, the middle number in the last group is made up in the same way as the middle number in the first two groups". In this case I would argue that your son's answer would be allowable - but it is not the standard approach and I would not encourage it.

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 Post subject: Re: Susan Daughtrey Pack 1 Test 3 q71Posted: Wed Oct 20, 2010 5:45 pm

Joined: Sat Oct 09, 2010 10:46 am
Posts: 182
hi turtleglos,
dd chose 28 as the answer when she was doing it as a multiple choice paper but gave 52 as the answer when i gave it as part of a standard test!

sgcmum.

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 Post subject: Re: Susan Daughtrey Pack 1 Test 3 q71Posted: Wed Oct 20, 2010 5:49 pm

Joined: Fri Oct 12, 2007 12:42 pm
Posts: 3810
52 was my first thought too, but 28 is equally valid.
26 cannot work as the 4 has not been used from the second set, but a totally reasonable error.

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 Post subject: Re: Susan Daughtrey Pack 1 Test 3 q71Posted: Wed Oct 27, 2010 4:51 pm

Joined: Mon Jan 30, 2006 4:07 pm
Posts: 2660
15[32]2 ) (14[30]2)
(12[?]4)

There are three credible answers to this question. Fortunately only one of the answers appears on the answer sheet. This question therefore should never be used in standard format.

15 x 2 = 30
30 plus 2 = 32

14 x 2 = 28
28 plus 2 = 30

12 x 4 = 48
48 plus 2 = 50

or:

15 plus 2 =17
17 plus the number on the left = 32

14 plus 2 = 16
16 plus the number on the left = 30

12 plus 4 = 16
16 plus the number on the left = 28

or

15 x 2 = 30
30 plus the number on the right = 32

14 x 2 = 28
28 plus the number on the right = 30

12 x 4 = 48
48 plus the number on the right = 52

Patricia

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