IPS TYPE Z iam stuck
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IPS TYPE Z iam stuck
could any one explain this for me please IPS A ,PAPER 1,TYPE Z, Q NO:31
three children have an amount of money between them.angela has £5.jason has one half of the total amount.danny has £2 more than angela.
the answer is D(Jason and danny have £19 between them)
three children have an amount of money between them.angela has £5.jason has one half of the total amount.danny has £2 more than angela.
the answer is D(Jason and danny have £19 between them)
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Re: IPS TYPE Z iam stuck
OK angela has £5 so Danny must have £7 pounds. total for Angela and Danny = £12.
Jason has half the total money so this must be £12 too. so Jason and Danny have £12+£7 = £19
Jason has half the total money so this must be £12 too. so Jason and Danny have £12+£7 = £19
Re: IPS TYPE Z iam stuck
thank you very much.i think you are right.
Re: IPS TYPE Z iam stuck
I find number lines and diagrams help me with this sort of question.
Re: IPS TYPE Z iam stuck
This is how I worked it out.
Angela = £5
Danny = £7 (Dannu has £2 more than Angela)
Jason = 1/2 of the total
So: 5 + 7 +1/2x = x (x being the total money)
12+1/2x = x
12 = x - 1/2x
12 = 1/2x
So, x = 24. So if total is 24, then Jason's money would be 1/2 of it, which is 12
Hence, Jason £12 + Danny £7 = £19
I hope it helps.
Angela = £5
Danny = £7 (Dannu has £2 more than Angela)
Jason = 1/2 of the total
So: 5 + 7 +1/2x = x (x being the total money)
12+1/2x = x
12 = x - 1/2x
12 = 1/2x
So, x = 24. So if total is 24, then Jason's money would be 1/2 of it, which is 12
Hence, Jason £12 + Danny £7 = £19
I hope it helps.
Re: IPS TYPE Z iam stuck
thank you very much replaymum.it really helped my DS to understand easily.
Re: IPS TYPE Z iam stuck
you are welcom senthi.
Good Luck
Good Luck