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PostPosted: Wed Jul 04, 2012 9:22 am 
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Joined: Fri Jul 16, 2010 11:54 am
Posts: 78
Can someone please help solve this

2(9)5 4(21)5 5(?)2

ans is 27

Also in this question

KJ is to IG as FC is to ?
Ans is BX

Thanks in advance.


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PostPosted: Wed Jul 04, 2012 9:35 am 
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Joined: Mon Feb 22, 2010 2:50 pm
Posts: 533
11+ novice wrote:
Can someone please help solve this

2(9)5 4(21)5 5(?)2

ans is 27

Also in this question

KJ is to IG as FC is to ?
Ans is BX

Thanks in advance.


For the first one 2 squared plus 5 = 9
4 squared plus 5 =21
5 squared plus2 =27

For the letters move back one letter with K and J and then 2 with I and G
With F and C move back 3 and then move back 4 in the same pattern to get the answer.


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PostPosted: Thu Jul 05, 2012 1:00 pm 
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Joined: Thu Jun 14, 2012 9:28 am
Posts: 121
Apologies in advance (to bel), but I would like a more detailed explanation for the letters question. Surely the question is asking our DC's to investigate a relationship bewteen two sets of letters.
Ideally, I would like to see the questions being asked without supplying the answers - as is the case with our DC's during the tests.


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PostPosted: Thu Jul 05, 2012 1:08 pm 
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Joined: Thu Jun 14, 2012 9:28 am
Posts: 121
I should have elaborated on my earlier post.
The only way I can fit the answer to the question is as follows :-
Taking the first letter in each case, K to I to F (jumps of -2 and -3 respectively so far) - and a jump of -4 would give the letter B. Similarly, looking at the second letters in each case, J to G to C (jumps of -3 and -4 so far) - and a jump of -5 would give X. Thus the answer is BX.
However, I worked this out given the answer and my solution would be more apt if the question was what is the next group of letters in the series, KJ, IG, FC, .....


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