Help with these questions

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11+ novice
Posts: 78
Joined: Fri Jul 16, 2010 12:54 pm

Help with these questions

Post by 11+ novice »

Can someone please help solve this

2(9)5 4(21)5 5(?)2

ans is 27

Also in this question

KJ is to IG as FC is to ?
Ans is BX

Thanks in advance.
Hera
Posts: 856
Joined: Mon Feb 22, 2010 3:50 pm

Re: Help with these questions

Post by Hera »

11+ novice wrote:Can someone please help solve this

2(9)5 4(21)5 5(?)2

ans is 27

Also in this question

KJ is to IG as FC is to ?
Ans is BX

Thanks in advance.
For the first one 2 squared plus 5 = 9
4 squared plus 5 =21
5 squared plus2 =27

For the letters move back one letter with K and J and then 2 with I and G
With F and C move back 3 and then move back 4 in the same pattern to get the answer.
Tagore
Posts: 121
Joined: Thu Jun 14, 2012 10:28 am

Re: Help with these questions

Post by Tagore »

Apologies in advance (to bel), but I would like a more detailed explanation for the letters question. Surely the question is asking our DC's to investigate a relationship bewteen two sets of letters.
Ideally, I would like to see the questions being asked without supplying the answers - as is the case with our DC's during the tests.
Tagore
Posts: 121
Joined: Thu Jun 14, 2012 10:28 am

Re: Help with these questions

Post by Tagore »

I should have elaborated on my earlier post.
The only way I can fit the answer to the question is as follows :-
Taking the first letter in each case, K to I to F (jumps of -2 and -3 respectively so far) - and a jump of -4 would give the letter B. Similarly, looking at the second letters in each case, J to G to C (jumps of -3 and -4 so far) - and a jump of -5 would give X. Thus the answer is BX.
However, I worked this out given the answer and my solution would be more apt if the question was what is the next group of letters in the series, KJ, IG, FC, .....
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