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PostPosted: Mon Dec 10, 2012 7:46 am 
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Joined: Fri Oct 05, 2012 7:02 am
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Hi, my daughter and I are trying to work out some type L questions for practice and have got a bit stuck.
Can anyone help?

The following question consists of 5 pairs

AA JT QI BF GQ we need to work out the next pair

We worked out a pattern from pair 1 to pair 3 to pair 5:
A to Q is -10
Q to G is -10
and
A to I is +8
I to Q is +8

So therefore we have worked out the pattern from pair 1 to pair 3 to pair 5 (odd numbered pairs) and so using our identified pattern we should be able to work out the pair for the 7th pair (WY)
Since there is only 5 pairs in the question the next one obviously has to be the sixth pair - we dont think that there is enough information to work out a pattern for the even numbered pairs because we only have pairs (2 and 4...JT and BF)

Are we overcomplicating this or missing something a bit more obvious?

thanks


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PostPosted: Mon Dec 10, 2012 9:35 am 
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Joined: Wed Jan 11, 2006 7:10 pm
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Location: Buckinghamshire
Where is the question from? (It always helps if you can tell us that.)

Type L questions, at least on GL Assessment papers, are never "every other one". You and your daughter have fought valiantly with it though, and possibly found the only logic there is to be had out of it. You are right to conclude that even if it was to be "every other one", you do not have enough information to get to the 6th pair.

There are definitely no mirror codes (which also occur very rarely, if ever on these questions), and therefore according to the "usual" rules" of a straightforward progression:

:: the first pairs are +9, +7, (+11/-15), +5

:: the second pairs are -7, -11, -3, +11

I am afraid that I can see no logic whatsoever there!

Even if someone can find a solution, it is a ridiculously over-complicated question. I suspect it is an error, though.


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PostPosted: Mon Dec 10, 2012 11:55 am 
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Location: Warwickshire
The best you can do with this is to assume that you've got two seperate series - and that if the first one series is behaving consistently, then the other will to.

JT -> BF = -8 / -14 or +12

so B-8 = T and F+12 = R

BF -> TR


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PostPosted: Mon Dec 10, 2012 12:16 pm 
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can't see the logic - even if it every 3rd pair then the jump is

AA -- BF = +1, +5
JT -- BF = -3, -3
QI -- VJ = +5, +1

What is the answers in the book/paper?


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PostPosted: Mon Dec 10, 2012 1:45 pm 
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Joined: Sun Sep 09, 2012 6:32 pm
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My guess is:

First letter: +9, +7, +11, +5
So I would now go +13
G +13 = T

Second letter: +19, +15, +23, +11
So I would now go +27
Q + 27 = R

My answer would be TR

And that would be the hardest question I have seen. I tried with - numbers for the second letter, but it just got even more confusing for me.

_________________
The more that you read, the more things you will know.
The more that you learn, the more places you'll go.
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PostPosted: Mon Dec 10, 2012 3:39 pm 
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Joined: Fri Oct 05, 2012 7:02 am
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Thanks All...at least we are not going mad!
My daughter received the question as a part of a list of practise questions from her 11 plus tutor group. (They are not marked as having come from a particular source)
I will check with the tutor and let you know

Thanks


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PostPosted: Wed Dec 12, 2012 10:18 am 
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Joined: Fri Oct 05, 2012 7:02 am
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Just to give you an update.
I have spoken to the tutor and the answer was to assume that you've got two separate series - and that if the first one series is behaving consistently, then the other will too.
Just as Okanagan suggested


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