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 Post subject: Help please with these questionsPosted: Mon Aug 26, 2013 8:52 pm

Joined: Sun Sep 23, 2012 11:51 pm
Posts: 112
(5 [60] 9) (7[71]8) (6 [?] 15) Answer should be 105
(24[51]18) (27[60]24) (17[?]28) Answer should be 54

Completely stumped by these, all help would be appreciated
Many thanks

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 Post subject: Re: Help please with these questionsPosted: Mon Aug 26, 2013 9:06 pm

Joined: Wed Jan 18, 2012 11:41 am
Posts: 4601
Location: Essex
(5 [60] 9) (7[71]8) (6 [?] 15) Answer should be 105
(24[51]18) (27[60]24) (17[?]28) Answer should be 54

Completely stumped by these, all help would be appreciated
Many thanks

(5 [60] 9) (7[71]8) (6 [?] 15)
First number*second number, add 15 = middle number

(24[51]18) (27[60]24) (17[?]28)
(First number + second number) + 9 = middle number

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 Post subject: Re: Help please with these questionsPosted: Mon Aug 26, 2013 9:12 pm

Joined: Sun Sep 23, 2012 11:51 pm
Posts: 112
(5 [60] 9) (7[71]8) (6 [?] 15) Answer should be 105
(24[51]18) (27[60]24) (17[?]28) Answer should be 54

Completely stumped by these, all help would be appreciated
Many thanks

(5 [60] 9) (7[71]8) (6 [?] 15)
First number*second number, add 15 = middle number

(24[51]18) (27[60]24) (17[?]28)
(First number + second number) + 9 = middle number

Thankyou, I just couldn't see it
I keep thinking the adding of another number at the end must come from amongst the trio of numbers, i.e. must be either A or C when (A [B] C), but I see it can be a random, just has to be applied in the same way .

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