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 Post subject: Type ZPosted: Fri Nov 01, 2013 2:24 pm

Joined: Sun Sep 09, 2012 7:57 pm
Posts: 40
Walsh Paper 4 MCQ

44 children took part in swimming gala.Rebecca came 6th.She tied with 4 other children.How many children did Rebecca beat?
Choices: 38 ;35; 34; 37; 33

How can this be worked out without knowing how many have tied for first to fifth?

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 Post subject: Re: Type ZPosted: Fri Nov 01, 2013 2:29 pm

Joined: Wed Jul 31, 2013 4:03 pm
Posts: 1382
Because if, for example, 2 children tied for second place the next child would be ranked 4th etc. So there would only ever be 5 children before her no matter where they came iyswim ... just like 11+ rankings!

Hope that helps - that's my understanding anyway.

JD

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 Post subject: Re: Type ZPosted: Fri Nov 01, 2013 2:34 pm

Joined: Sun Feb 03, 2013 9:41 pm
Posts: 87
I think if there were any other ties the question would have specified. As it hasn't I would assume that Rebecca and the other 4 children at position 6 are the only ties. Therefore, 5 children beat them plus Rebecca and the other 4 = 10 children position 6 or higher. Thus Rebecca beat 34 children (44 -10)

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 Post subject: Re: Type ZPosted: Fri Nov 01, 2013 2:38 pm

Joined: Sun Feb 03, 2013 9:41 pm
Posts: 87
Ahhh! Good point jamesdean, didn't think of that!

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 Post subject: Re: Type ZPosted: Fri Nov 01, 2013 2:48 pm

Joined: Sun Sep 09, 2012 7:57 pm
Posts: 40
JamesDean wrote:
Because if, for example, 2 children tied for second place the next child would be ranked 4th etc. So there would only ever be 5 children before her no matter where they came iyswim ... just like 11+ rankings!

Thanks to both of you.
I thought in competitions, even if there is a tie, the ordinal number wouldn't change.
For eg; in Olympics, even if there is a tie for silver, wouldn't they give a bronze for the 3rd position? Or is that bronze given for 4th position? Bit confused

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 Post subject: Re: Type ZPosted: Fri Nov 01, 2013 2:54 pm

Joined: Wed Jul 31, 2013 4:03 pm
Posts: 1382
Although its rare for a dead heat, it does happen and then only 3 medals are given, of whatever colour. Here's a link to the 2000 summer Olympic men's 50m freestyle swimming final - 2 gold and 1 bronze awarded:

http://en.wikipedia.org/wiki/Swimming_a ... _freestyle

JD

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 Post subject: Re: Type ZPosted: Fri Nov 01, 2013 3:29 pm

Joined: Sat Apr 20, 2013 5:27 am
Posts: 241
Does it really work like this?

In a competition if 2 children share the 2nd prize, the 4th child would get the third prize, doesn't he?

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 Post subject: Re: Type ZPosted: Fri Nov 01, 2013 3:37 pm

Joined: Wed Jul 31, 2013 4:03 pm
Posts: 1382
wildwest wrote:
Does it really work like this?

In order to answer mjames' original question, I think we have to assume it does or else it is impossible!

JD

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 Post subject: Re: Type ZPosted: Fri Nov 01, 2013 3:45 pm

Joined: Sat Apr 20, 2013 5:27 am
Posts: 241
I guess... If 33 wasn't in the options then it would have been straightforward

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 Post subject: Re: Type ZPosted: Fri Nov 01, 2013 3:46 pm

Joined: Sun Sep 09, 2012 7:57 pm
Posts: 40
Thanx JamesDean , for your time and patience for the explanation.....and the source!!!
I liked your 11+ ranking analogy as well.
Funnily my kids got that right, it's only me going overboard!!!

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