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Question 28 - HABS Maths paper 2014

Posted: Wed Jan 07, 2015 11:40 pm
by AML
please help is there any trick to working out this question??

Re: Question 28 - HABS Maths paper 2014

Posted: Wed Jan 07, 2015 11:52 pm
by AML
Here's the question -

We write s(2,5) as an abbreviation for 2+3+4+5 so that s(2,5) = 14

Similarly

S(6,39) = 6+7+8+9+....+ 38 + 39 = 765

Work out:

s(1,3) =
s(6,40) =
s(7, 38) =

s(1,2) - s(2,3) + S (3,4) - s(4,5)+ ......... - S (18,19) + S (19,20) =

Re: Question 28 - HABS Maths paper 2014

Posted: Thu Jan 08, 2015 12:00 am
by Guest55
We've had this before - try searching.

Re: Question 28 - HABS Maths paper 2014

Posted: Thu Jan 08, 2015 1:07 am
by DebsB
The long way round is this:

Total = (number of items) x (mean value)

For s(a,b):
number of items = b-a+1
mean value = (a+b)/2
This gives total = (b-a+1)(a+b)/2

So
s(1,3) = 1+2+3 = 6
Check the formula works: s(1,3)=(3-1+1)*(4/2)=3*2=6

Then
s(6,40)=(40-6+1)*(46/2)=35*23=805
s(7,38)=(38-7+1)*(45/2)=32*22.5=720
or alternatively s(7,38)=s(6,40)-6-39-40=805-85=720

The short way is to use the example they have given of s(6,39)=765, like this:
s(1,3)=1+2+3=6
s(6,40)=s(6,39)+40=765+40=805
s(7,38)=s(6,39)-6-39=765-45=720

Re: Question 28 - HABS Maths paper 2014

Posted: Thu Jan 08, 2015 7:38 am
by rah_b92
This is one of those "can you spot the short way" type questions. DebsB has wonderfully given the short way to do the second and third questions, using the answer they have already given for s(6,39).

And in the final question, they're looking to see if you spot that most of the terms cancel each other out:

s(1,2) - s(2,3) + s(3,4) - s(4,5)+ ......... - s(18,19) + s(19,20)
= 1 + 2 - 2 - 3 + 3 + 4 - 4 - 5 + ... - 18 - 19 + 19 + 20
= 1 + 20
= 21

Re: Question 28 - HABS Maths paper 2014

Posted: Thu Jan 08, 2015 11:48 am
by DebsB
rah_b92 wrote:This is one of those "can you spot the short way" type questions. DebsB has wonderfully given the short way to do the second and third questions, using the answer they have already given for s(6,39).

And in the final question, they're looking to see if you spot that most of the terms cancel each other out:

s(1,2) - s(2,3) + s(3,4) - s(4,5)+ ......... - s(18,19) + s(19,20)
= 1 + 2 - 2 - 3 + 3 + 4 - 4 - 5 + ... - 18 - 19 + 19 + 20
= 1 + 20
= 21
Nicely done, rah_b92. I hadn't even noticed that the final question was there. :oops: Shocking example of failure to read the question properly - let's hope none of our kids have been throwing marks away by missing stuff out in that way!

Re: Question 28 - HABS Maths paper 2014

Posted: Thu Jan 08, 2015 12:53 pm
by AML
thank you everyone