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PostPosted: Sat Jan 10, 2009 12:24 am 
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Joined: Fri Mar 07, 2008 11:23 pm
Posts: 435
A child scores 101 raw score with an age standardized score of 216.

216/101 = 2.138614 – the standardizing factor.

Pass mark 221 age standardized score translates as 221/2.138614= 104 raw score.

Therefore although child misses by 5 (standardized) marks, they only actually needed to get three more questions correct to pass.

Are my calculations correct, or have I (as I suspect) rather naiively over simplified everything?
B x


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PostPosted: Sat Jan 10, 2009 7:42 am 
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Joined: Mon Feb 12, 2007 1:21 pm
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To standardise in Maths you calculate:

(score - mean) divided by standard deviation this then gives a number which I believe is then manipulated in some way depending on the LA.


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PostPosted: Sat Jan 10, 2009 11:41 am 
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Joined: Fri Mar 17, 2006 5:12 pm
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Location: Birmingham
Hi Bougalou

There is not a simple conversion factor.

However an Age Standarded score of 216 will almost certainly be the sum of 2 Standardisations (with an average of 108 which is the 70th percentile of candidates)

If one of the raw scores was 101 then you need to find out what the other raw score was for the other exam component and what each of the respective Age Standaised Scores were which resulted in a total of 216.

The LEA should tell you this.

You can also request the Age Standised Conversation tables for the exam from the LEA, if necessary under the Freedom of Information Act.

Regards


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PostPosted: Sat Jan 10, 2009 8:00 pm 
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Hi Ken, 101 was the total raw score for verbal and non verbal reasoning (55Vr and 46 nvr) which resulted in the standardised score of 216. 221 was the pass mark.
bouga


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