Maths question
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Maths question
Hello fellow parents...
I have come across a question in one of the papers which I am finding difficult to work out - can someone please assist. The problem question is:
Zainab has £5 more than David
David has £1.50 more than Maria
Altogether Zainab, David and Maria have £13.10
How much money has Maria got?
It would also help if you could explain the calculation...
Thanking you in advance
I have come across a question in one of the papers which I am finding difficult to work out - can someone please assist. The problem question is:
Zainab has £5 more than David
David has £1.50 more than Maria
Altogether Zainab, David and Maria have £13.10
How much money has Maria got?
It would also help if you could explain the calculation...
Thanking you in advance
Maths problem
Sorry Tulip... although I do not know the answer as there was no answer pack with the exam paper, your answer cannot be right...
Any other ideas please?
Any other ideas please?
Not very good at explanations but I'll give it a try:
Let z, d and m replace the names
From the question, we get:
z = d + 5 Equation One
d = m + 1.5 Equation Two
z + d + m = 13.1 Equation Three
We want to find out how much Maria has, so every equation has to include "m".
We can replace the "d" in Equation One with its equivalent "m + 1.5", so equation one now reads: z = m + 1.5 + 5
Now we know that "m" is in each of the equations, we can replace it in Equation Three, so:
m + 1.5 + 5 + m + 1.5 + m = 13.1
Instead of:
z + d + m = 13.1
If you work that out, it comes to:
3m + 8 = 13.1 which can be solved like a normal equation:
3m + 8 = 13.1
3m = 5.1 (minus
m = 1.7 (divide by 3)
So the answer is Maria has £1.70. (Of course, if you wanted to know how much the others had, just work it out some more)
Rather long winded, but gets to the point.
Hope it helps!
LQ
Let z, d and m replace the names
From the question, we get:
z = d + 5 Equation One
d = m + 1.5 Equation Two
z + d + m = 13.1 Equation Three
We want to find out how much Maria has, so every equation has to include "m".
We can replace the "d" in Equation One with its equivalent "m + 1.5", so equation one now reads: z = m + 1.5 + 5
Now we know that "m" is in each of the equations, we can replace it in Equation Three, so:
m + 1.5 + 5 + m + 1.5 + m = 13.1
Instead of:
z + d + m = 13.1
If you work that out, it comes to:
3m + 8 = 13.1 which can be solved like a normal equation:
3m + 8 = 13.1
3m = 5.1 (minus
m = 1.7 (divide by 3)
So the answer is Maria has £1.70. (Of course, if you wanted to know how much the others had, just work it out some more)
Rather long winded, but gets to the point.
Hope it helps!
LQ
Maths question
Thanks...thats brilliant.
Please explain how you worked it out if you do not mind...
Please explain how you worked it out if you do not mind...
To Lulu Queen
Apologies. Was responding to Tiredmum.