bracket maths help
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bracket maths help
night before help with....
(3 [8] 4) (3 [14] 7)
(5 [ ? ] 6)
how is answer 21 (from Susan Daughtreys paper 8.
(3 [8] 4) (3 [14] 7)
(5 [ ? ] 6)
how is answer 21 (from Susan Daughtreys paper 8.
Also, 'first number minus 1 times second number' works and is possibly easier as it keeps the numbers smaller. Essentially, we don't need that extra 4 or 7 or 6 in the first place if we just have to deduct it at the end.patricia wrote:(3 [8] 4) (3 [14] 7)
(5 [ ? ] 6)
3 x 4 = 12 – 4 = 8
3 x 7 = 21 – 7 = 14
5 x 6 = 30 – 6 = 24
Multiplying numbers outside the middle brackets, subtracting number on the right.
(3 - 1) x 4 = 2 x 4 = 8
(3 - 1) x 7 = 2 x 7 = 14
(5 - 1) x 6 = 4 x 6 = 24