Question 28 - HABS Maths paper 2014

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AML
Posts: 347
Joined: Fri Sep 19, 2014 5:32 pm

Question 28 - HABS Maths paper 2014

Post by AML »

please help is there any trick to working out this question??
AML
Posts: 347
Joined: Fri Sep 19, 2014 5:32 pm

Re: Question 28 - HABS Maths paper 2014

Post by AML »

Here's the question -

We write s(2,5) as an abbreviation for 2+3+4+5 so that s(2,5) = 14

Similarly

S(6,39) = 6+7+8+9+....+ 38 + 39 = 765

Work out:

s(1,3) =
s(6,40) =
s(7, 38) =

s(1,2) - s(2,3) + S (3,4) - s(4,5)+ ......... - S (18,19) + S (19,20) =
Guest55
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Joined: Mon Feb 12, 2007 2:21 pm

Re: Question 28 - HABS Maths paper 2014

Post by Guest55 »

We've had this before - try searching.
DebsB
Posts: 144
Joined: Sun Sep 22, 2013 7:25 pm
Location: Cheltenham

Re: Question 28 - HABS Maths paper 2014

Post by DebsB »

The long way round is this:

Total = (number of items) x (mean value)

For s(a,b):
number of items = b-a+1
mean value = (a+b)/2
This gives total = (b-a+1)(a+b)/2

So
s(1,3) = 1+2+3 = 6
Check the formula works: s(1,3)=(3-1+1)*(4/2)=3*2=6

Then
s(6,40)=(40-6+1)*(46/2)=35*23=805
s(7,38)=(38-7+1)*(45/2)=32*22.5=720
or alternatively s(7,38)=s(6,40)-6-39-40=805-85=720

The short way is to use the example they have given of s(6,39)=765, like this:
s(1,3)=1+2+3=6
s(6,40)=s(6,39)+40=765+40=805
s(7,38)=s(6,39)-6-39=765-45=720
rah_b92
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Joined: Mon Mar 03, 2014 1:10 pm

Re: Question 28 - HABS Maths paper 2014

Post by rah_b92 »

This is one of those "can you spot the short way" type questions. DebsB has wonderfully given the short way to do the second and third questions, using the answer they have already given for s(6,39).

And in the final question, they're looking to see if you spot that most of the terms cancel each other out:

s(1,2) - s(2,3) + s(3,4) - s(4,5)+ ......... - s(18,19) + s(19,20)
= 1 + 2 - 2 - 3 + 3 + 4 - 4 - 5 + ... - 18 - 19 + 19 + 20
= 1 + 20
= 21
DebsB
Posts: 144
Joined: Sun Sep 22, 2013 7:25 pm
Location: Cheltenham

Re: Question 28 - HABS Maths paper 2014

Post by DebsB »

rah_b92 wrote:This is one of those "can you spot the short way" type questions. DebsB has wonderfully given the short way to do the second and third questions, using the answer they have already given for s(6,39).

And in the final question, they're looking to see if you spot that most of the terms cancel each other out:

s(1,2) - s(2,3) + s(3,4) - s(4,5)+ ......... - s(18,19) + s(19,20)
= 1 + 2 - 2 - 3 + 3 + 4 - 4 - 5 + ... - 18 - 19 + 19 + 20
= 1 + 20
= 21
Nicely done, rah_b92. I hadn't even noticed that the final question was there. :oops: Shocking example of failure to read the question properly - let's hope none of our kids have been throwing marks away by missing stuff out in that way!
AML
Posts: 347
Joined: Fri Sep 19, 2014 5:32 pm

Re: Question 28 - HABS Maths paper 2014

Post by AML »

thank you everyone
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