Help with question
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Help with question
Please can anyone advise how to approach this question and is there a formula which can be used to solve it,please?
The cost of 2 full fares and 1 half fare is £55. Find the full fare and the half fare.
Thanks for any help.
The cost of 2 full fares and 1 half fare is £55. Find the full fare and the half fare.
Thanks for any help.
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help required with maths question
7 boxes each contain 16 coins
7 boxes each contain 14 coins
10 boxes each contain 9 coins
so total no of coins is 300
share these coins equally between 3 people without opening the boxes
7 boxes each contain 14 coins
10 boxes each contain 9 coins
so total no of coins is 300
share these coins equally between 3 people without opening the boxes
Not sure if there is a clever way to do this, but first note that 16+9=25 so give one person 4 boxes of 16 and 4 boxes of 9 = 4 X 25 = 100
Then have 3 boxes of 16 left - so possible multiples are 16, 32, 48
All 7 boxes of 14 left, multiples 14, 28, 42, 56, 70, 84
AHA !! = notice that 16 plus 84 = 100
so 2nd person has 1 box of 16 and 6 boxes of 14
3rd person has remaining 2 boxes of 16, 1 box of 14 and 6 boxes of 9, check that works 32+14+54 = 100
Then have 3 boxes of 16 left - so possible multiples are 16, 32, 48
All 7 boxes of 14 left, multiples 14, 28, 42, 56, 70, 84
AHA !! = notice that 16 plus 84 = 100
so 2nd person has 1 box of 16 and 6 boxes of 14
3rd person has remaining 2 boxes of 16, 1 box of 14 and 6 boxes of 9, check that works 32+14+54 = 100
Re: help required with maths question
100 coins each, so each person must receive an even number of boxes of 9s, with the rest of their 100 made up of 14s and 16s. (They could just as well have said 5 boxes of 18s.) However not all even numbers can be made up from 14s and 16s, and those up to 100 that can can be done in only one way. So consider the different numbers of 9s and how the rest might be made up:fusspot99 wrote:7 boxes each contain 16 coins
7 boxes each contain 14 coins
10 boxes each contain 9 coins
so total no of coins is 300
share these coins equally between 3 people without opening the boxes
100 - 0x9 = 100 = 6x14 + 16
100 - 2x9 = 82, which can't be done
100 - 4x9 = 64 = 4x16
100 - 6x9 = 46 = 14 + 2x16
100 - 8x9 = 28 = 2x14
100 - 10x9 = 10, which can't be done
Eight 9s are impossible because two 9s can't be done. So the only possibility is to allocate 0, 4 and 6 nines, with the rest allocated as above.