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PostPosted: Thu Jan 05, 2017 8:15 pm 
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Joined: Sun Oct 18, 2015 10:00 pm
Posts: 40
I've just seen Deverill's posts about MT Maths paper... I've kept the answers from when we did this paper couple of weeks ago, so that it will be easier for DD2 when time comes...

Thought it might be worth sharing what we have:

Merchant Taylor 2009 paper

1. a) 7751 b) 2394 c) 4 1/10
2. a) 19 b) 16
3. 30
4. 0.04, 0.042, 0.204, 0.24, 0.40
5. a) -6, -2, 2, 4, 5, 7, 14 b) 20 degrees c) -13
6. a) 33, 40 b) -1, -4 c) 162, 486
7. a) 236cm2 b) 12cm
8 2 and 1/4 mile
9. £81 each
10. 0.36 away
11. £242
12. a) even b) not even c) even d) even
13. x= 70, y= 81
14. a) 4x3+2 b) (3+5)/ (4-2) or (3-5)+(4+2)
15. 28 years old
16.a) 9 b) 9 c) 11
17. a) (bottom left shape) largest perimeter b) bottom right= smallest area
18. a) 3 b) 6
19. a) 20 dogs, b) 6 kennels
20. 8 combinations
21.a) 9 b) 30 people c) -- d) 86 people
22. a) 32 b) 54 c) y=6 d) z= 8 e) 3 and 5, 9 and 2, 4 and 4, 1 and 10, 0 and 20, 19 and 1.
23. a) isosceles triangle b) D= 6,3
24 a) 50, b) £20 c) 268g d) 700g
25. a) 100,000 b) 8 days
26. a) Wednesday b) Monday c) Tuesday
27. a) 28 b) no because only number left would be 1
28. horses= 5; people= 7
29. 192 cubes
30. b= 36, x= 67.5, y= 33.5
31. a) ACEF b) DCAB or BACD c) BACDFE


Regards


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PostPosted: Thu Jan 05, 2017 9:24 pm 
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Joined: Wed Jan 04, 2017 2:58 pm
Posts: 37
Thank you so much, do you have he other specimen paper answers also? At least I can double check all my answers so far. This is my first time using this site - wish I joined sooner!


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PostPosted: Thu Jan 05, 2017 11:02 pm 
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Joined: Mon Feb 12, 2007 1:21 pm
Posts: 13554
23a) Is it right angled as well?

31a) should be a distance


For number 9 as the numbers are close I did not add them but guessed 80 then adjusted my answer.


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PostPosted: Fri Jan 06, 2017 11:08 am 
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Joined: Wed Jan 04, 2017 2:58 pm
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Yes I thought 31a and c are answered in distance?
Can you let me know how you worked out 28? The horses and head question.


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PostPosted: Fri Jan 06, 2017 11:18 am 
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Joined: Thu Mar 12, 2015 4:11 pm
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List all the multiples of 4 and all the multiples of 2. Then identify which combination of 4s and 2s add up to the total number of legs required. (5x4)+(7x2).


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PostPosted: Fri Jan 06, 2017 12:27 pm 
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Joined: Thu Aug 07, 2014 2:54 pm
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Thank you very much Northdad, for sharing.


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PostPosted: Fri Jan 06, 2017 5:51 pm 
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Joined: Mon Feb 12, 2007 1:21 pm
Posts: 13554
I didn't do it like that. I drew circles for heads and gave them all two legs then looked at how many 'extra' legs I had - this is double the number of horses. [They each need two more]


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PostPosted: Mon Jan 09, 2017 6:09 am 
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Joined: Mon Jan 09, 2017 6:06 am
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Hi
for 31c) we got FDCEBA which is 32km......


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