Help please :)
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Help please :)
Hi everyone, you helped me before with a math sum so was hoping if you could help again.
There are 4 cards with the numbers, 7, 5, 2, 3.
Using each card only once, make the smallest possible multiple of 6.
I think I am missing something obvious but I'm having a thick day
There are 4 cards with the numbers, 7, 5, 2, 3.
Using each card only once, make the smallest possible multiple of 6.
I think I am missing something obvious but I'm having a thick day
Re: Help please :)
7 5 2 3
Well you can't make 0x6 so far as I can see, so let's try for 6 ....... how about 7 - (2x3 - 5) = 7 + 5 - 2x3 ........ just saw that by looking as I saw that 2x3 = 6, the difference between 5 and 6 is one, and I needed to get the 7 down by one to get to 6 if you see what I mean.
Is this a bit like that game on TV - Countdown?
Well you can't make 0x6 so far as I can see, so let's try for 6 ....... how about 7 - (2x3 - 5) = 7 + 5 - 2x3 ........ just saw that by looking as I saw that 2x3 = 6, the difference between 5 and 6 is one, and I needed to get the 7 down by one to get to 6 if you see what I mean.
Is this a bit like that game on TV - Countdown?
Re: Help please :)
Yes I think they must be asking for operators, because it obviously isn't just putting the numbers into sequence.
7+5+2+3 = 17.
17 isn't divisible by 3, so no combination of these numbers (regardless of order) can possibly make a number divisible by 6 since all numbers with 6 as a factor will have 3 as a factor too.
7+5+2+3 = 17.
17 isn't divisible by 3, so no combination of these numbers (regardless of order) can possibly make a number divisible by 6 since all numbers with 6 as a factor will have 3 as a factor too.
Last edited by Okanagan on Thu Aug 30, 2012 12:09 pm, edited 1 time in total.
Re: Help please :)
18 is my guess.
7+5 = 12 / 2 = 6 x 3 = 18
7+5 = 12 / 2 = 6 x 3 = 18
Re: Help please :)
Oh I see - I thought it was asking for each card to be used once. There were 2 other questions using the same cards - 1) make the smallest possible even number and 2) make a number as close as possible to 4000. So I assumed it was using all 4 but couldn't see how??
Re: Help please :)
Yes, this is where I got stumped - because the sum of numbers was 17 so impossible. Just a badly worded question thenOkanagan wrote:Yes I think they must be asking for operators, because it obviously isn't just putting the numbers into sequence.
7+5+2+3 = 17.
17 isn't divisible by 3, so no combination of these numbers (regardless of order) can possibly make a number divisible by 6 since all numbers with 6 as a factor will have 3 as a factor too.
Re: Help please :)
My answer uses all 4 once.
I make the lowest even number 2
7-5 = 2
3 - 2 (from above) =1
1 (from above ) x 2 = 2
Too much time spent watching countdown I am afraid.
I make the lowest even number 2
7-5 = 2
3 - 2 (from above) =1
1 (from above ) x 2 = 2
Too much time spent watching countdown I am afraid.
Re: Help please :)
(5 x 2) - (7+ 3) = 0.mystery wrote:7 5 2 3
Well you can't make 0x6 so far as I can see
Re: Help please :)
Now a debate as to whether 0 is an even number or divisible by 6
Is there are lower even number than 2 or
a lower multiple of 6 than 18?
Really curious now as just love these questions.
Working on the 4000 now whilst sewing on name tapes!
Is there are lower even number than 2 or
a lower multiple of 6 than 18?
Really curious now as just love these questions.
Working on the 4000 now whilst sewing on name tapes!
Re: Help please :)
smallest possible even number 3 - (7-5)/2
smallest multiple of 6 - 7 - (5-3)/2
smallest multiple of 6 - 7 - (5-3)/2