kentlady wrote:

Hi

Please can anyone help me with this problem. i think it is a ratio problem which for the life of me i cannot work out.

A cash box contains some coins to the value of £5.25.

There are twice as many 5p coins as 2p coins, and twice as many 2p coins as 1p coins.

This means there are:

1. how many 5p coins

2. how many 2p coins

3. how many 1p coins

Please help.

*If there are two 5p coins then there is one 2p coin (the ratio is 2:1)

*If there are two 2p coins then there is one 1p coin (the ratio is 2:1)

Which can also be rewritten as:

*If there are four 5p coins, then there are two 2p coins and one 1p coin (the ratio is 4:2:1, we are taking all the coins into account to form a ratio)

*If we write this in the form of an equation it will be like this:

4(5p) + 2(2p) + 1(1p) = 20p + 4p + 1p = 25p

*Now that you know that this gives you 25p you have to do:

5.25/0.25 = 21

*This means the following equation occurs 21 times:

4(5p) + 2(2p) + 1(1p) = 20p + 4p + 1p = 25p

*Therefore there are:

21 x 4(5p) = 84 x 5p coins

21 x 2(2p) = 42 x 2p coins

21 x 1(1p) = 21 x 1p coins

(84 x 5) + (42 x 2) + (21 x 2) = 525p