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 Post subject: Maths problemPosted: Mon Dec 24, 2007 5:26 pm

Joined: Thu Mar 15, 2007 12:14 pm
Posts: 5
Hello
can anyone help please with maths question 48, from Maths familiarization test 11c NFER
What is the formula for the area of a hexagon with side y and x.
How does one approach this? Find area of a triangle, or area of trapezium?
Or is it simpler than that?
Many thanks for any help.
KK

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 Post subject: Posted: Thu Dec 27, 2007 10:54 am

Joined: Thu Jan 12, 2006 3:29 pm
Posts: 625
Hi KK

I think the question has a side of x and a perpendicular height of y

I would suggest using the formula for a triangle

1/2 height x base

1/2 x y x x

Then multiply by 6

to give

3 x y x x

or

3yx

Normally written as 3xy

Regards

Mike

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 Post subject: Posted: Thu Dec 27, 2007 11:23 am
Mike that is right up to a point. But when you multiply 1/2xy by 6 you get 3xy. There should be no addition involved.

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 Post subject: Posted: Thu Dec 27, 2007 12:03 pm

Joined: Thu Mar 15, 2007 12:14 pm
Posts: 5
Thank you mike and guest,
The clue was in x is the perpendicular height, and as mike has pointed out the area of the triangle is 1/2 base x height.
1/2 x Y x X= 1/2YX
The hexagon can be divided into 6 triangles,giving
= 1/2YX
= (1/2YX)6
=3YX or 3XY

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 Post subject: Posted: Thu Dec 27, 2007 1:16 pm

Joined: Mon Jun 18, 2007 2:32 pm
Posts: 7137
Location: East Kent
sorryit took me so long to reply KK!
i was trying to find teh paper amongst the Christmas debris.

Just pipped atthe post I see

exactly area =1/2 (xy) fpr each triangle, there are 6 so 3(xy)

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 Post subject: Posted: Fri Dec 28, 2007 2:41 pm

Joined: Thu Jan 12, 2006 3:29 pm
Posts: 625
Hi

Original post has been edited, apologies for any confusion.

Regards

Mike

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 Post subject: Posted: Fri Dec 28, 2007 4:47 pm

Joined: Thu Mar 15, 2007 12:14 pm
Posts: 5
Thanks yoyo

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