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11 Plus Maths – Preparation and Information

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Bananaperson
Posts: 14
Joined: Sun Apr 08, 2018 2:10 pm

Help

Post by Bananaperson »

Hi,

My child is practicing as many maths papers as possible. This question came up in a paper for the city girls school. I’m finding it challenging(im not a maths person) any help would be greatly appreciated
:) what method should be used? Trial and error? Or algebra?
Paper below!
Question 48(last one)
https://www.clsg.org.uk/attachments/dow ... 5&type=pdf

Banana person
Last edited by Bananaperson on Mon Apr 09, 2018 5:32 pm, edited 1 time in total.
anotherdad
Posts: 1763
Joined: Mon Jan 24, 2011 5:33 pm

Re: Help

Post by anotherdad »

This is the way I tackled it:

Since circle+triangle=square, you can substitute a square in place of (circle+triangle) in line 3 to give circle+square=hexagon.

From line 2, you can then deduce that circle=square because we now have circle+square=hexagon in line 3 as well as square+square=hexagon in line 2. In other words, adding a circle to a square has the same effect (resulting in a hexagon) as adding a square to a square.

From line 1, now we know that circle=square, that must mean that triangle=0 because adding triangle to a circle doesn't change its value.

(which means that circle=1, square=1 and hexagon=2)
Bananaperson
Posts: 14
Joined: Sun Apr 08, 2018 2:10 pm

Re: Help

Post by Bananaperson »

Ahh i see..
Thanks :)
Decisiontime639
Posts: 50
Joined: Fri Jul 14, 2017 11:41 am
Location: London

Re: Help

Post by Decisiontime639 »

Id use substitution knowing what a square equals, etc.
daddyof3
Posts: 80
Joined: Sat Oct 17, 2015 10:46 am

Re: Help

Post by daddyof3 »

Hello all

I tried to get my daughter to complete the paper above. Does anyone know where I can get the answers?

I would really appreciate it.
Guest55
Posts: 16254
Joined: Mon Feb 12, 2007 2:21 pm

Re: Help

Post by Guest55 »

Post any questions you are unsure of and I'll check them.
daddyof3
Posts: 80
Joined: Sat Oct 17, 2015 10:46 am

Re: Help

Post by daddyof3 »

Thank you Guest55 I will have a look and get to you.
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