11 Plus Exams Forum

Please can any one explain how to solve this type of question?

1. Can you find numbers to replace A, B and C in this sum? (A,B and C are different numbers)

A B C
A B C
+ A B C
____________
B B B

2. Can you find a four digit number which is reversed when multiplied by 9? (i.e. ABCD X 9 = DCBA)

I think q1 is not correct.

Q2. A has to be 1 otherwise any number time 9 will make 5 digits number. Therefore D is 9. B has to be 0 because any number times with 9 will have carry forward and make 5 digit number. And C is 8. The number is 1089.

Hope that helps.

Thank you for your help. I have the answer to Q1 and the question is correct. I am trying to understand a way to explain the solution to DS in a simplified way than trying to guess all possible outcomes.

Thank you

With question 1, this is how I did it but I am not a maths teacher and I don't know if there is a better way to teach/explain it.
BBB has to be divisible by 3 as ABC X 3 = BBB.
You can rule out 999, 666 and 333 because they don't give an ABC answer. You can rule out 111 because that wouldn't give a 3 figure answer.
So I started to do 222÷3, 444÷3, 555 ÷3 etc until I got to the number that had the middle number the same as the B.
Hope that makes sense.

Hope that makes sense.

Yes it does make perfect make sense.

Thank you so much

worrybot wrote:Thank you for your help. I have the answer to Q1 and the question is correct. I am trying to understand a way to explain the solution to DS in a simplified way than trying to guess all possible outcomes.

Thank you

Sorry I’m wrong. Tried to do in my head. Loobylow gave perfect answer.