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 Post subject: Help- type 19 (k) questionsPosted: Sat Dec 04, 2010 10:47 am

Joined: Wed Aug 25, 2010 2:58 pm
Posts: 550
Can anyone help solve these:

27 (20) 11 16 (12) 8 6 (?) 18

9 (15) 45 25 (12) 50 16 (?) 32

12 (16) 3 28 (32) 7 4 (?) 1

Thanks

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 Post subject: Re: Help- type 19 (k) questionsPosted: Sat Dec 04, 2010 11:31 am

Joined: Mon Oct 18, 2010 9:01 am
Posts: 155
Top one - not sure - could it be:

27 - 11 = 16 + 4 = 20
etc.
6 - 18 = -12 + 4 = -8 ??

12 divided by 3 = 4 Add 4 to 16
28 divided by 7 = 4 Add 4 to 28
4 divided by 1 =4 Add 4 to 4

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 Post subject: Re: Help- type 19 (k) questionsPosted: Sat Dec 04, 2010 11:35 am

Joined: Mon Oct 18, 2010 9:01 am
Posts: 155
second one is 45 - 9 = 36 - 1 and halve it

etc.

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 Post subject: Re: Help- type 19 (k) questionsPosted: Sat Dec 04, 2010 11:55 am

Joined: Fri Oct 30, 2009 11:08 pm
Posts: 1234
The third one is

divide 1st number by 2nd then add the first number so

4/1 = 4 +4 = 8

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 Post subject: Re: Help- type 19 (k) questionsPosted: Sat Dec 04, 2010 12:15 pm

Joined: Fri Oct 30, 2009 11:08 pm
Posts: 1234
DD says number 2 is

divide second number by first and add 10

32/16 = 2 +10 = 12

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 Post subject: Re: Help- type 19 (k) questionsPosted: Sat Dec 04, 2010 3:01 pm

Joined: Mon Jan 30, 2006 4:07 pm
Posts: 2661
Always keep to basic rules...

Middle number has been made using the numbers either side.
Same rule must apply for all 3 sets.
Sometimes 1 operation. Sometimes 2.
Second operation can be:

1] + - x / [divide sign!] the same number.
2] doubling/halving
3] + - x / [divide sign] the number on the left or right of the middle number.

Whilst teaching, I always say:

If the number in the middle is bigger than the 2 either side then your 1st operation is probably adding or multiplying.

If the number in the middle is smaller that at least one of the numbers either side, then your 1st operation is probably subtracting or dividing.

I always emphasise the word probably, because there are times when this rule will not work, they are not to panic, if it doesn't work, that’s fine, just try the other 2 operations.

27 (20) 11 16 (12) 8 6 (?) 18

Assuming the numbers in the 3rd bracket are the wrong way round 18 (?) 6 or the incorrect numbers given.

27 minus 11 = 16 add 4 = 20
16 minus 8 = 8 add 4 =12
18 minus 6 = 12 add 4 = 16

9 (15) 45 25 (12) 50 16 (?) 32

45 divided by 9 = 5 add 10 = 15
50 divided by 25 = 2 add 10 = 12
32 divided by 16 = 2 add 10 = 12

12 (16) 3 28 (32) 7 4 (?) 1

12 divided by 3 = 4 add the number on the left of the middle number = 16
28 divided by 7 = 4 add the number on the left of the middle number = 32
4 divided by 1 = 4 add the number on the left of the middle number = 8

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 Post subject: Re: Help- type 19 (k) questionsPosted: Sat Dec 04, 2010 8:25 pm

Joined: Wed Aug 25, 2010 2:58 pm
Posts: 550
Thank you!! I can sleep tonight!

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 Post subject: Re: Help- type 19 (k) questionsPosted: Tue Dec 07, 2010 4:55 pm

Joined: Tue Nov 23, 2010 11:00 pm
Posts: 20
I am not sure whether I should start a new topic for this, but can you please help me with these?

( 13 [ 10 ] 3 )( 17 [ 21 ] 10 )( 20 [ ? ] 7 )
( 3 [ 10 ] 7 )( 9 [ 27 ] 3 ) ( 8 [ ? ] 8 )

Thanks and Regards
Lakshmi

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 Post subject: Re: Help- type 19 (k) questionsPosted: Tue Dec 07, 2010 6:14 pm

Joined: Fri Oct 30, 2009 11:08 pm
Posts: 1234
No.1 Add both numbers together then subtract 6

20 + 7 -6 = 21

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 Post subject: Re: Help- type 19 (k) questionsPosted: Tue Dec 07, 2010 7:47 pm

Joined: Mon Oct 18, 2010 9:01 am
Posts: 155
Minesatea wrote:
No.1 Add both numbers together then subtract 6

20 + 7 -6 = 21

That's wrong - it doesn't work on the last one.

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