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 Post subject: Type P & Type K HelpPosted: Fri Oct 19, 2007 11:08 am
Help......

Type P

1 8 5 11 7 12 7 [?]

and

6 13 28 59 122 [?]

this Type K has us baffled

(17 [32] 2) second bracket (13 [36] 3)
what is the ans (9 [? ]4)

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 Post subject: Posted: Fri Oct 19, 2007 11:56 am
Type P

1 8 5 11 12 7 () - answer = +7 -3
+6 -4
+5 -5

Type P

6 13 28 59 122 () -answer = x2 +1
x2 +2
x2 +3
x2 +4

Type K

Times the two numbers outside the brackets and take away the smaller number.
17 x 2 =34-2 =32
13x3=39-3=36
9x4=36-4=32

Hope this helps

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 Post subject: Posted: Fri Oct 19, 2007 12:07 pm

Joined: Thu Nov 30, 2006 8:48 pm
Posts: 18
Location: Berks/Bucks
Thank you Guest - follow bottom two....

but the first one we still can't seem to understand!!!

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 Post subject: Posted: Fri Oct 19, 2007 12:43 pm

Joined: Thu Oct 11, 2007 7:59 am
Posts: 893
Location: Cloud 9

1 8 5 11 7 12 7 11
+7 -3 +6 -4 +5 -5 +6

Does this help?? Always write the steps out then it becomes clear!

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 Post subject: Posted: Fri Oct 19, 2007 12:54 pm
1 8 5 11 12 7
+7 -3 +6 +1 +5 +5

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 Post subject: Posted: Fri Oct 19, 2007 1:25 pm
Sorry missed out a letter in the sequence:

1 8 5 11 7 12 7 ()

1+7 = 8 -3 =5
5+6 =11-4=7
7+5= 12-5=7
7+4=11

The first column of adding is decreasing by +1 each time.
The second part of the sum is increasing by -1 each time.[/b]

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 Post subject: Posted: Sun Oct 21, 2007 8:45 pm
Another type P has me baffled:

225 64 27 8 ?

The answer is 1 but I'm damned if I can see why.

Can anyone help?

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 Post subject: Posted: Sun Oct 21, 2007 8:49 pm

Joined: Mon Feb 12, 2007 1:21 pm
Posts: 13027
They are the cube numbers backwards

5 cubed [225], 4 cubed [64], 3 cubed [27], 2 cubed [8]

so next number is 1 cubed = 1x1x1 = 1

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 Post subject: Posted: Fri Oct 26, 2007 3:16 pm
Surely 5 cubed is 125 not 225? Or am I just stupid.

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 Post subject: Posted: Fri Oct 26, 2007 3:30 pm

Joined: Sun Sep 02, 2007 11:14 am
Posts: 10
Yes, it looks like there is an error in the original question.
225 64 27 8 should be 125 64 27 8 ?

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