Grammar 2019 wrote:
We are stumped however for this one below:
5 [10] 4
3 [14] 8
2 [2] 6
We thought the solution was outside numbers multiplied then subtract 10, but as 10 is not one of the outside numbers I don’t think that can be correct.
Thanks so much for any help or tips on these question types.
Your assumption is correct. The 10 is a "missing operator": although it doesn't appear in the question, the same rule (multiply and subtract 10) can be applied to each set of numbers and it is therefore a valid answer. What cannot happen is for there to be a different rule for any of the sets of numbers.