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 Post subject: Same rule for the 2nd set of numbers?Posted: Mon Jul 14, 2008 9:44 am

Joined: Thu Jan 10, 2008 2:59 pm
Posts: 11
Using the same rules for the 1st set of numbers, find the missing number in the 2nd set of numbers.

(a) 3 [12] 48 5 [ ] 80 the answer is [color=red]20[/color]

(b) 100 [20] 4 150 [ ] 6 the answer is [color=red]30[/color]

(c) 3 [15] 75 4 [ ] 100 the answer is [color=red]20[/color]

I can not work out the rules or the patten can any one help please?

Mr Zee

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 Post subject: Posted: Mon Jul 14, 2008 10:05 am

Joined: Thu Jan 12, 2006 3:29 pm
Posts: 625
Hi

(a) multiply then square root

48 x 3 = 144
square root = 12

80 x 5 = 400
square root = 20

Same rule for (b) and (c)

Regards

Mike

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Mike Edwards is a co-author of The Tutors product range.

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 Post subject: Posted: Mon Jul 14, 2008 10:59 am

Joined: Thu Jan 10, 2008 2:59 pm
Posts: 11
Thanks Mike
Mr Zee

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 Post subject: Re: Same rule for the 2nd set of numbers?Posted: Mon Jul 14, 2008 1:52 pm

Joined: Tue Jan 01, 2008 1:05 pm
Posts: 515
Mr Zee wrote:
Using the same rules for the 1st set of numbers, find the missing number in the 2nd set of numbers.

(a) 3 [12] 48 5 [ ] 80 the answer is 20

(b) 100 [20] 4 150 [ ] 6 the answer is 30

(c) 3 [15] 75 4 [ ] 100 the answer is 20

I can not work out the rules or the patten can any one help please?

Mr Zee

?
a) 3x4=12
12x4 =48

5x4=[20]
20x4=80

b) divide by 5

c) multiply by 5

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 Post subject: Posted: Thu Sep 25, 2008 10:54 pm

Joined: Mon Jun 16, 2008 5:34 pm
Posts: 548
Square Root?

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