Three groups of numbers

[scary mum]

My DS & I are struggling with the type

X(y)z A(b)c d(?)f

Has anyone posted a logical approach to this that we can follow. I will ask his tutor to go through it with me next week, but in the meantime one of his questions is beating me!

[999 mum]

let us know what the question is then!

[stevew61]

(e)

Have a look here.


http://www.elevenplusexams.co.uk/forum/ ... f=3&t=3740" onclick="window.open(this.href);return false;

http://www.elevenplusexams.co.uk/forum/ ... =3&t=20671" onclick="window.open(this.href);return false;

Probably one of the hardest type of question as it involves a good grounding in KS2 maths and a bit of trial and error..........on a personal level I can crack them in the morning but not late in the evening.

[scary mum]

Thanks - they are the only type he really has trouble with I'm worried he will get bogged down with them. The first one we had trouble with was:

25(50)5 24(40)6 27( )3

I think this one is divide the number on the left by the one on the right and add 10 (took about 10 mins to get that!)

The second one is:

6(15)11 9(16)15 4( )11

I will be embarrassed when someone shows me how easy it is

[999 mum]

25(50)5 24(40)6 27( )3

using the format a(c)b

c=a/b*10 (the left number divided by the right number multiplied by 10)

so I make the answer 90

[scary mum]

Yes, sorry I got that one, I just didn't put the answer!! I wrote add 10 instead of multiply by- sorry! And the other one?

[pheasantchick]

I think the answer is 17.

Ie. a(b)c.

b = (c-a) + 10

[scary mum]

Thank you. It all looks so simple when you see it.

[copella]

The second one, you take the left number from the right one and add ten. 11-6=5 5 + 10=15.