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 Post subject: Maths q - pythagoras' theoremPosted: Mon Nov 19, 2018 7:55 pm

Joined: Thu Mar 06, 2014 2:50 pm
Posts: 164
How do you find the missing side length of a right angle triangle when only one length(the longest length) is known? In this case 10cm
The 2 unknown sides are of equal length.

Any help would be gratefully appreciated

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 Post subject: Re: Maths q - pythagoras' theoremPosted: Mon Nov 19, 2018 7:59 pm

Joined: Mon Feb 12, 2007 2:21 pm
Posts: 16254
OK - so Pythagoras says @the square on the hypotenuse = sum of the squares on the other two sides"

So 10^2 = the other two sides .... but we know they are equal so each 'square' must be ....?

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 Post subject: Re: Maths q - pythagoras' theoremPosted: Mon Nov 19, 2018 8:05 pm

Joined: Thu Mar 06, 2014 2:50 pm
Posts: 164
I'm clearly being really stupid here so apologies in advance.
I'm trying to help DD but she's in the shower at the moment.
The answer in the book states the missing sides are 7.07 but I can't get to this at all. Dd is getting 3.16

Last edited by kal12003 on Mon Nov 19, 2018 8:12 pm, edited 1 time in total.

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 Post subject: Re: Maths q - pythagoras' theoremPosted: Mon Nov 19, 2018 8:11 pm

Joined: Mon Feb 12, 2007 2:21 pm
Posts: 16254
So 10 ^ 2 = 100 so two equal things squared = 100. What will each be?

How do you then find the length of a side from this?

[I do know what the answer is but am trying to avoid unnecessary algebra]

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 Post subject: Re: Maths q - pythagoras' theoremPosted: Mon Nov 19, 2018 8:28 pm

Joined: Thu Mar 06, 2014 2:50 pm
Posts: 164
Thank you for your help, Dd is still struggling so she's going to go to maths club at school tomorrow

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 Post subject: Re: Maths q - pythagoras' theoremPosted: Mon Nov 19, 2018 8:33 pm

Joined: Mon Feb 12, 2007 2:21 pm
Posts: 16254
Call the unknown side a

Then a^2 + a^2 = 10^2 = 100

So a^2 = ...

a =

[ Off out in a minute so rushing]

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