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 Post subject: Sevenoaks paper Math 2016Posted: Thu Aug 01, 2019 12:13 am

Joined: Wed Jun 12, 2019 2:26 pm
Posts: 21
there are couple of questions
16) Find the area of the shaded region in the diagram below.Give your answer in terms of pi
it's a semi cicrcle of diameter 10cm then there is another circle in it.(ANSWER 6.25 PI)

25)Asquare is divided into 3 congruent rectangles.The middle of rectangle is removed and replaced on the side of the original square to form an octagon as shown.
what is the ration of the perimeter of the sqaure to octagon? ( ANSWER 3:5)

27) In the magic square which uses all whole numbers from 7-15 each of the rows columns and diagonals have same total?What is the number of n?7

n
7
14

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 Post subject: Re: Sevenoaks paper Math 2016Posted: Thu Aug 01, 2019 1:16 am

Joined: Mon Dec 24, 2018 3:27 pm
Posts: 45
Sulikhan wrote:
there are couple of questions
16) Find the area of the shaded region in the diagram below.Give your answer in terms of pi
it's a semi cicrcle of diameter 10cm then there is another circle in it.(ANSWER 6.25 PI)

25)Asquare is divided into 3 congruent rectangles.The middle of rectangle is removed and replaced on the side of the original square to form an octagon as shown.
what is the ration of the perimeter of the sqaure to octagon? ( ANSWER 3:5)

27) In the magic square which uses all whole numbers from 7-15 each of the rows columns and diagonals have same total?What is the number of n?7

n
7
14

Q16: Look at picture we can see radius of big circle is 5 and radius of small circle is 2.5. The area of shade is 1/2 big circle- small circle.

Q25: look at picture we can see the long side of rectangle is 3 times the short. Let’s call short one is 1, therefore long one is 3. The perimeter of square is 3x4. The octagon is 20. Ratio is 3/5.

Q27: the total of magic square is 7+8+...15=99 so any line is 99:3=33. Look at picture the top right corner is 33-7-14=12. 15 can not be same line with 14 and 12 because that line will be more than 33, therefore 15 is in middle of left column just under n. Therefore the center number is 33-15-7=11 and n= 33-11-14=8.

Hope that helps.

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 Post subject: Re: Sevenoaks paper Math 2016Posted: Thu Aug 01, 2019 10:14 am

Joined: Wed Jun 12, 2019 2:26 pm
Posts: 21
Wow!!!! Thank u soo much. You are very good.

I just also wanted if you know the solutions for
The Haberdashers Asked boys school, Elstree, Herts maths paper year 2011
Questions
16, 17,18 25,26,27
Quite hard paper

Hope someone knows the explanations
Many tbanks

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 Post subject: Re: Sevenoaks paper Math 2016Posted: Thu Aug 01, 2019 3:20 pm

Joined: Mon Dec 24, 2018 3:27 pm
Posts: 45
Look at school website they don’t have 2011 paper therefore I can’t help you. Sorry about that.

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 Post subject: Re: Sevenoaks paper Math 2016Posted: Thu Aug 01, 2019 7:06 pm

Joined: Wed Jun 12, 2019 2:26 pm
Posts: 21
Qeb2019 wrote:
Look at school website they don’t have 2011 paper therefore I can’t help you. Sorry about that.

Hi
Please could I send you the paper and answers and then you could see if you can help
Me???
Many thanks

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